Base | Representation |
---|---|
bin | 10011000101001101… |
… | …01001101110000001 |
3 | 222102221100000100021 |
4 | 21202212221232001 |
5 | 131440010442423 |
6 | 4412305253441 |
7 | 511601360521 |
oct | 114246515601 |
9 | 28387300307 |
10 | 10244234113 |
11 | 438766a793 |
12 | 1b9a934281 |
13 | c734915b9 |
14 | 6d277b681 |
15 | 3ee55395d |
hex | 2629a9b81 |
10244234113 has 2 divisors, whose sum is σ = 10244234114. Its totient is φ = 10244234112.
The previous prime is 10244234093. The next prime is 10244234159. The reversal of 10244234113 is 31143244201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8702650944 + 1541583169 = 93288^2 + 39263^2 .
It is an emirp because it is prime and its reverse (31143244201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10244234113 - 217 = 10244103041 is a prime.
It is not a weakly prime, because it can be changed into another prime (10244234213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5122117056 + 5122117057.
It is an arithmetic number, because the mean of its divisors is an integer number (5122117057).
Almost surely, 210244234113 is an apocalyptic number.
It is an amenable number.
10244234113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10244234113 is an equidigital number, since it uses as much as digits as its factorization.
10244234113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 10244234113 its reverse (31143244201), we get a palindrome (41387478314).
The spelling of 10244234113 in words is "ten billion, two hundred forty-four million, two hundred thirty-four thousand, one hundred thirteen".
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