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102443313031 = 3141617130633
BaseRepresentation
bin101111101101000011…
…0001110011110000111
3100210102110011111121221
41133122012032132013
53134300442004111
6115021203421211
710254432536053
oct1373206163607
9323373144557
10102443313031
113a49a641374
1217a30084807
139877a81bb7
144d5b756c63
1529e89b9371
hex17da18e787

102443313031 has 16 divisors (see below), whose sum is σ = 108503555328. Its totient is φ = 96563174400.

The previous prime is 102443313017. The next prime is 102443313053. The reversal of 102443313031 is 130313344201.

It is a cyclic number.

It is not a de Polignac number, because 102443313031 - 27 = 102443312903 is a prime.

It is a super-2 number, since 2×1024433130312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 102443312987 and 102443313005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102443311031) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 718891 + ... + 849523.

It is an arithmetic number, because the mean of its divisors is an integer number (6781472208).

Almost surely, 2102443313031 is an apocalyptic number.

102443313031 is a deficient number, since it is larger than the sum of its proper divisors (6060242297).

102443313031 is a wasteful number, since it uses less digits than its factorization.

102443313031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131322.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 102443313031 its reverse (130313344201), we get a palindrome (232756657232).

The spelling of 102443313031 in words is "one hundred two billion, four hundred forty-three million, three hundred thirteen thousand, thirty-one".

Divisors: 1 31 41 617 1271 19127 25297 130633 784207 4049623 5355953 80600561 166034543 2498617391 3304623001 102443313031