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102443321331314 = 251221660665657
BaseRepresentation
bin10111010010101111110001…
…110001110000111001110010
3111102201111010012110101202222
4113102233301301300321302
5101411412410230100224
61001513451230241042
730402200000606645
oct2722576161607162
9442644105411688
10102443321331314
112a706a72221807
12b5a6251056182
13452149620b5b2
141b423d71a1a5c
15bc9bbc545b5e
hex5d2bf1c70e72

102443321331314 has 4 divisors (see below), whose sum is σ = 153664981996974. Its totient is φ = 51221660665656.

The previous prime is 102443321331313. The next prime is 102443321331331. The reversal of 102443321331314 is 413133123344201.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 60384633270025 + 42058688061289 = 7770755^2 + 6485267^2 .

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (102443321331313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25610830332827 + ... + 25610830332830.

Almost surely, 2102443321331314 is an apocalyptic number.

102443321331314 is a deficient number, since it is larger than the sum of its proper divisors (51221660665660).

102443321331314 is an equidigital number, since it uses as much as digits as its factorization.

102443321331314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51221660665659.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 102443321331314 its reverse (413133123344201), we get a palindrome (515576444675515).

The spelling of 102443321331314 in words is "one hundred two trillion, four hundred forty-three billion, three hundred twenty-one million, three hundred thirty-one thousand, three hundred fourteen".

Divisors: 1 2 51221660665657 102443321331314