Base | Representation |
---|---|
bin | 10111010010101111110001… |
… | …110001110000111001110010 |
3 | 111102201111010012110101202222 |
4 | 113102233301301300321302 |
5 | 101411412410230100224 |
6 | 1001513451230241042 |
7 | 30402200000606645 |
oct | 2722576161607162 |
9 | 442644105411688 |
10 | 102443321331314 |
11 | 2a706a72221807 |
12 | b5a6251056182 |
13 | 452149620b5b2 |
14 | 1b423d71a1a5c |
15 | bc9bbc545b5e |
hex | 5d2bf1c70e72 |
102443321331314 has 4 divisors (see below), whose sum is σ = 153664981996974. Its totient is φ = 51221660665656.
The previous prime is 102443321331313. The next prime is 102443321331331. The reversal of 102443321331314 is 413133123344201.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 60384633270025 + 42058688061289 = 7770755^2 + 6485267^2 .
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (102443321331313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25610830332827 + ... + 25610830332830.
Almost surely, 2102443321331314 is an apocalyptic number.
102443321331314 is a deficient number, since it is larger than the sum of its proper divisors (51221660665660).
102443321331314 is an equidigital number, since it uses as much as digits as its factorization.
102443321331314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51221660665659.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 102443321331314 its reverse (413133123344201), we get a palindrome (515576444675515).
The spelling of 102443321331314 in words is "one hundred two trillion, four hundred forty-three billion, three hundred twenty-one million, three hundred thirty-one thousand, three hundred fourteen".
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