Base | Representation |
---|---|
bin | 10011000101001110… |
… | …00100000101110011 |
3 | 222102221112111111221 |
4 | 21202213010011303 |
5 | 131440022422011 |
6 | 4412311445511 |
7 | 511602320452 |
oct | 114247040563 |
9 | 28387474457 |
10 | 10244342131 |
11 | 4387733961 |
12 | 1b9a986897 |
13 | c734cb80a |
14 | 6d27a8b99 |
15 | 3ee575971 |
hex | 2629c4173 |
10244342131 has 2 divisors, whose sum is σ = 10244342132. Its totient is φ = 10244342130.
The previous prime is 10244342113. The next prime is 10244342153. The reversal of 10244342131 is 13124344201.
Together with previous prime (10244342113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10244342131 - 29 = 10244341619 is a prime.
It is a super-2 number, since 2×102443421312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10244342096 and 10244342105.
It is not a weakly prime, because it can be changed into another prime (10244342161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5122171065 + 5122171066.
It is an arithmetic number, because the mean of its divisors is an integer number (5122171066).
Almost surely, 210244342131 is an apocalyptic number.
10244342131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10244342131 is an equidigital number, since it uses as much as digits as its factorization.
10244342131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 10244342131 its reverse (13124344201), we get a palindrome (23368686332).
The spelling of 10244342131 in words is "ten billion, two hundred forty-four million, three hundred forty-two thousand, one hundred thirty-one".
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