Base | Representation |
---|---|
bin | 1001010100101100110010… |
… | …0101111000010001000001 |
3 | 1100022000012110100121201211 |
4 | 2111023030211320101001 |
5 | 2320424001424400423 |
6 | 33445203020530121 |
7 | 2105424620054413 |
oct | 225131445702101 |
9 | 40260173317654 |
10 | 10251224450113 |
11 | 32a2579a53809 |
12 | 119690a3b0941 |
13 | 5948bcabc6ba |
14 | 27623a3d69b3 |
15 | 12b9d04c710d |
hex | 952cc978441 |
10251224450113 has 2 divisors, whose sum is σ = 10251224450114. Its totient is φ = 10251224450112.
The previous prime is 10251224450053. The next prime is 10251224450119. The reversal of 10251224450113 is 31105442215201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8816997851649 + 1434226598464 = 2969343^2 + 1197592^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10251224450113 is a prime.
It is not a weakly prime, because it can be changed into another prime (10251224450119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5125612225056 + 5125612225057.
It is an arithmetic number, because the mean of its divisors is an integer number (5125612225057).
Almost surely, 210251224450113 is an apocalyptic number.
It is an amenable number.
10251224450113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10251224450113 is an equidigital number, since it uses as much as digits as its factorization.
10251224450113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 10251224450113 its reverse (31105442215201), we get a palindrome (41356666665314).
The spelling of 10251224450113 in words is "ten trillion, two hundred fifty-one billion, two hundred twenty-four million, four hundred fifty thousand, one hundred thirteen".
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