Base | Representation |
---|---|
bin | 1001010100101101000100… |
… | …1111110110010101101011 |
3 | 1100022000101220100001220111 |
4 | 2111023101033312111223 |
5 | 2320424131423424011 |
6 | 33445214451035151 |
7 | 2105426556022342 |
oct | 225132117662553 |
9 | 40260356301814 |
10 | 10251302561131 |
11 | 32a260a054775 |
12 | 119693059bab7 |
13 | 59490303b038 |
14 | 27624692ab59 |
15 | 12b9d72a6121 |
hex | 952d13f656b |
10251302561131 has 2 divisors, whose sum is σ = 10251302561132. Its totient is φ = 10251302561130.
The previous prime is 10251302561117. The next prime is 10251302561141. The reversal of 10251302561131 is 13116520315201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10251302561131 - 211 = 10251302559083 is a prime.
It is a super-2 number, since 2×102513025611312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10251302561093 and 10251302561102.
It is not a weakly prime, because it can be changed into another prime (10251302561141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5125651280565 + 5125651280566.
It is an arithmetic number, because the mean of its divisors is an integer number (5125651280566).
Almost surely, 210251302561131 is an apocalyptic number.
10251302561131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10251302561131 is an equidigital number, since it uses as much as digits as its factorization.
10251302561131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
Adding to 10251302561131 its reverse (13116520315201), we get a palindrome (23367822876332).
The spelling of 10251302561131 in words is "ten trillion, two hundred fifty-one billion, three hundred two million, five hundred sixty-one thousand, one hundred thirty-one".
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