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10251302561131 is a prime number
BaseRepresentation
bin1001010100101101000100…
…1111110110010101101011
31100022000101220100001220111
42111023101033312111223
52320424131423424011
633445214451035151
72105426556022342
oct225132117662553
940260356301814
1010251302561131
1132a260a054775
12119693059bab7
1359490303b038
1427624692ab59
1512b9d72a6121
hex952d13f656b

10251302561131 has 2 divisors, whose sum is σ = 10251302561132. Its totient is φ = 10251302561130.

The previous prime is 10251302561117. The next prime is 10251302561141. The reversal of 10251302561131 is 13116520315201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10251302561131 - 211 = 10251302559083 is a prime.

It is a super-2 number, since 2×102513025611312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10251302561093 and 10251302561102.

It is not a weakly prime, because it can be changed into another prime (10251302561141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5125651280565 + 5125651280566.

It is an arithmetic number, because the mean of its divisors is an integer number (5125651280566).

Almost surely, 210251302561131 is an apocalyptic number.

10251302561131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10251302561131 is an equidigital number, since it uses as much as digits as its factorization.

10251302561131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 10251302561131 its reverse (13116520315201), we get a palindrome (23367822876332).

The spelling of 10251302561131 in words is "ten trillion, two hundred fifty-one billion, three hundred two million, five hundred sixty-one thousand, one hundred thirty-one".