Base | Representation |
---|---|
bin | 1001010100110110010100… |
… | …1010110111011001000011 |
3 | 1100022020210212010120212211 |
4 | 2111031211022313121003 |
5 | 2320444222234021231 |
6 | 33450305023002551 |
7 | 2105545222222225 |
oct | 225154512673103 |
9 | 40266725116784 |
10 | 10253784282691 |
11 | 32a3672a03924 |
12 | 1197303739457 |
13 | 594c0a23a831 |
14 | 276400380415 |
15 | 12bad00c0eb1 |
hex | 953652b7643 |
10253784282691 has 2 divisors, whose sum is σ = 10253784282692. Its totient is φ = 10253784282690.
The previous prime is 10253784282641. The next prime is 10253784282733. The reversal of 10253784282691 is 19628248735201.
10253784282691 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10253784282691 - 213 = 10253784274499 is a prime.
It is not a weakly prime, because it can be changed into another prime (10253784282641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5126892141345 + 5126892141346.
It is an arithmetic number, because the mean of its divisors is an integer number (5126892141346).
It is a 1-persistent number, because it is pandigital, but 2⋅10253784282691 = 20507568565382 is not.
Almost surely, 210253784282691 is an apocalyptic number.
10253784282691 is a deficient number, since it is larger than the sum of its proper divisors (1).
10253784282691 is an equidigital number, since it uses as much as digits as its factorization.
10253784282691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11612160, while the sum is 58.
The spelling of 10253784282691 in words is "ten trillion, two hundred fifty-three billion, seven hundred eighty-four million, two hundred eighty-two thousand, six hundred ninety-one".
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