Base | Representation |
---|---|
bin | 1001010100111011010001… |
… | …1100100001011001010011 |
3 | 1100022101020112211001001212 |
4 | 2111032310130201121103 |
5 | 2321004433230430001 |
6 | 33451045014050335 |
7 | 2105623202250425 |
oct | 225166434413123 |
9 | 40271215731055 |
10 | 10255114311251 |
11 | 32a4195750a87 |
12 | 11976150499ab |
13 | 59508c95a794 |
14 | 2764c8c7a815 |
15 | 12bb5bc437bb |
hex | 953b4721653 |
10255114311251 has 4 divisors (see below), whose sum is σ = 10277073871272. Its totient is φ = 10233154751232.
The previous prime is 10255114311223. The next prime is 10255114311289. The reversal of 10255114311251 is 15211341155201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10255114311251 - 230 = 10254040569427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10255114313251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10979779310 + ... + 10979780243.
It is an arithmetic number, because the mean of its divisors is an integer number (2569268467818).
Almost surely, 210255114311251 is an apocalyptic number.
10255114311251 is a deficient number, since it is larger than the sum of its proper divisors (21959560021).
10255114311251 is an equidigital number, since it uses as much as digits as its factorization.
10255114311251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21959560020.
The product of its (nonzero) digits is 6000, while the sum is 32.
Adding to 10255114311251 its reverse (15211341155201), we get a palindrome (25466455466452).
The spelling of 10255114311251 in words is "ten trillion, two hundred fifty-five billion, one hundred fourteen million, three hundred eleven thousand, two hundred fifty-one".
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