Base | Representation |
---|---|
bin | 11101111000110101000… |
… | …00011100101101000011 |
3 | 10122011201100100121221001 |
4 | 32330122200130231003 |
5 | 113311134111210124 |
6 | 2103434240512431 |
7 | 134123402050165 |
oct | 16743240345503 |
9 | 3564640317831 |
10 | 1026941897539 |
11 | 366583a24318 |
12 | 14704091b717 |
13 | 75abcc1504c |
14 | 379c0682935 |
15 | 1baa6b70b44 |
hex | ef1a81cb43 |
1026941897539 has 2 divisors, whose sum is σ = 1026941897540. Its totient is φ = 1026941897538.
The previous prime is 1026941897461. The next prime is 1026941897627. The reversal of 1026941897539 is 9357981496201.
1026941897539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1026941897539 - 211 = 1026941895491 is a prime.
It is not a weakly prime, because it can be changed into another prime (1026941897239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 513470948769 + 513470948770.
It is an arithmetic number, because the mean of its divisors is an integer number (513470948770).
It is a 1-persistent number, because it is pandigital, but 2⋅1026941897539 = 2053883795078 is not.
Almost surely, 21026941897539 is an apocalyptic number.
1026941897539 is a deficient number, since it is larger than the sum of its proper divisors (1).
1026941897539 is an equidigital number, since it uses as much as digits as its factorization.
1026941897539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29393280, while the sum is 64.
The spelling of 1026941897539 in words is "one trillion, twenty-six billion, nine hundred forty-one million, eight hundred ninety-seven thousand, five hundred thirty-nine".
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