Base | Representation |
---|---|
bin | 101111111101101001… |
… | …0010001101111111001 |
3 | 100211212020220020121212 |
4 | 1133323102101233321 |
5 | 3141421012322223 |
6 | 115152334012505 |
7 | 10304303401646 |
oct | 1377322215771 |
9 | 324766806555 |
10 | 103000120313 |
11 | 3a755978982 |
12 | 17b66647135 |
13 | 993623696c |
14 | 4db1698dcd |
15 | 2a2c804278 |
hex | 17fb491bf9 |
103000120313 has 2 divisors, whose sum is σ = 103000120314. Its totient is φ = 103000120312.
The previous prime is 103000120291. The next prime is 103000120331. The reversal of 103000120313 is 313021000301.
Together with next prime (103000120331) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102561343504 + 438776809 = 320252^2 + 20947^2 .
It is a cyclic number.
It is not a de Polignac number, because 103000120313 - 216 = 103000054777 is a prime.
It is not a weakly prime, because it can be changed into another prime (103000128313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51500060156 + 51500060157.
It is an arithmetic number, because the mean of its divisors is an integer number (51500060157).
Almost surely, 2103000120313 is an apocalyptic number.
It is an amenable number.
103000120313 is a deficient number, since it is larger than the sum of its proper divisors (1).
103000120313 is an equidigital number, since it uses as much as digits as its factorization.
103000120313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 103000120313 its reverse (313021000301), we get a palindrome (416021120614).
The spelling of 103000120313 in words is "one hundred three billion, one hundred twenty thousand, three hundred thirteen".
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