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10300121323147 is a prime number
BaseRepresentation
bin1001010111100010111100…
…0100101001011010001011
31100110200102011110010122101
42111320233010221122023
52322224122024320042
633523451014334231
72112105415451515
oct225705704513213
940420364403571
1010300121323147
113311290a66187
1211a429595a377
135993b3155376
14278758412bb5
1512cde30b96b7
hex95e2f12968b

10300121323147 has 2 divisors, whose sum is σ = 10300121323148. Its totient is φ = 10300121323146.

The previous prime is 10300121323123. The next prime is 10300121323189. The reversal of 10300121323147 is 74132312100301.

10300121323147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10300121323147 - 239 = 9750365509259 is a prime.

It is not a weakly prime, because it can be changed into another prime (10300121323747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5150060661573 + 5150060661574.

It is an arithmetic number, because the mean of its divisors is an integer number (5150060661574).

Almost surely, 210300121323147 is an apocalyptic number.

10300121323147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10300121323147 is an equidigital number, since it uses as much as digits as its factorization.

10300121323147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 10300121323147 its reverse (74132312100301), we get a palindrome (84432433423448).

The spelling of 10300121323147 in words is "ten trillion, three hundred billion, one hundred twenty-one million, three hundred twenty-three thousand, one hundred forty-seven".