Base | Representation |
---|---|
bin | 101111111101101011… |
… | …0110110111010011001 |
3 | 100211212100011020210221 |
4 | 1133323112312322121 |
5 | 3141421314233423 |
6 | 115152415440041 |
7 | 10304316532555 |
oct | 1377326667231 |
9 | 324770136727 |
10 | 103001321113 |
11 | 3a756619079 |
12 | 17b66b26021 |
13 | 99365673b2 |
14 | 4db18cc865 |
15 | 2a2c98ee5d |
hex | 17fb5b6e99 |
103001321113 has 2 divisors, whose sum is σ = 103001321114. Its totient is φ = 103001321112.
The previous prime is 103001321099. The next prime is 103001321119. The reversal of 103001321113 is 311123100301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74249710144 + 28751610969 = 272488^2 + 169563^2 .
It is a cyclic number.
It is not a de Polignac number, because 103001321113 - 25 = 103001321081 is a prime.
It is not a weakly prime, because it can be changed into another prime (103001321119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51500660556 + 51500660557.
It is an arithmetic number, because the mean of its divisors is an integer number (51500660557).
Almost surely, 2103001321113 is an apocalyptic number.
It is an amenable number.
103001321113 is a deficient number, since it is larger than the sum of its proper divisors (1).
103001321113 is an equidigital number, since it uses as much as digits as its factorization.
103001321113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 103001321113 its reverse (311123100301), we get a palindrome (414124421414).
The spelling of 103001321113 in words is "one hundred three billion, one million, three hundred twenty-one thousand, one hundred thirteen".
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