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103003113 = 334334371
BaseRepresentation
bin1100010001110…
…11001111101001
321011211002201010
412020323033221
5202332044423
614115414133
72360340423
oct610731751
9234732633
10103003113
1153162844
122a5b4349
13184556b5
14d973813
159099693
hex623b3e9

103003113 has 4 divisors (see below), whose sum is σ = 137337488. Its totient is φ = 68668740.

The previous prime is 103003097. The next prime is 103003141. The reversal of 103003113 is 311300301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 103003113 - 24 = 103003097 is a prime.

It is a super-3 number, since 3×1030031133 (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103003163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17167183 + ... + 17167188.

It is an arithmetic number, because the mean of its divisors is an integer number (34334372).

Almost surely, 2103003113 is an apocalyptic number.

It is an amenable number.

103003113 is a deficient number, since it is larger than the sum of its proper divisors (34334375).

103003113 is an equidigital number, since it uses as much as digits as its factorization.

103003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34334374.

The product of its (nonzero) digits is 27, while the sum is 12.

The square root of 103003113 is about 10149.0449304356. The cubic root of 103003113 is about 468.7595371571.

Adding to 103003113 its reverse (311300301), we get a palindrome (414303414).

The spelling of 103003113 in words is "one hundred three million, three thousand, one hundred thirteen".

Divisors: 1 3 34334371 103003113