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103013312113 is a prime number
BaseRepresentation
bin101111111110000010…
…0100110011001110001
3100211220011201110101001
41133330010212121301
53141432401441423
6115153524442001
710304523464005
oct1377404463161
9324804643331
10103013312113
113a762369098
1217b6ab49301
139938ba526a
144db3330705
152a2da5ccad
hex17fc126671

103013312113 has 2 divisors, whose sum is σ = 103013312114. Its totient is φ = 103013312112.

The previous prime is 103013312093. The next prime is 103013312123. The reversal of 103013312113 is 311213310301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87866594929 + 15146717184 = 296423^2 + 123072^2 .

It is an emirp because it is prime and its reverse (311213310301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103013312113 is a prime.

It is a super-2 number, since 2×1030133121132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103013312123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51506656056 + 51506656057.

It is an arithmetic number, because the mean of its divisors is an integer number (51506656057).

Almost surely, 2103013312113 is an apocalyptic number.

It is an amenable number.

103013312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

103013312113 is an equidigital number, since it uses as much as digits as its factorization.

103013312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 103013312113 its reverse (311213310301), we get a palindrome (414226622414).

The spelling of 103013312113 in words is "one hundred three billion, thirteen million, three hundred twelve thousand, one hundred thirteen".