10302103113 has 4 divisors (see below), whose sum is σ = 13736137488. Its totient is φ = 6868068740.

The previous prime is 10302103109. The next prime is 10302103129. The reversal of 10302103113 is 31130120301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10302103113 - 2² = 10302103109 is a prime.

It is a super-2 number, since 2×10302103113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10302103092 and 10302103101.

It is not an unprimeable number, because it can be changed into a prime (10302103313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1717017183 + ... + 1717017188.

It is an arithmetic number, because the mean of its divisors is an integer number (3434034372).

Almost surely, 2^10302103113 is an apocalyptic number.

It is an amenable number.

10302103113 is a deficient number, since it is larger than the sum of its proper divisors (3434034375).

10302103113 is an equidigital number, since it uses as much as digits as its factorization.

10302103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3434034374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10302103113 its reverse (31130120301), we get a palindrome (41432223414).

The spelling of 10302103113 in words is "ten billion, three hundred two million, one hundred three thousand, one hundred thirteen".