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1030210311331 is a prime number
BaseRepresentation
bin11101111110111010101…
…00011101010010100011
310122111011010110020202201
432333131110131102203
5113334332314430311
62105134434154031
7134300400106315
oct16773524352243
93574133406681
101030210311331
11367a00954a43
121477b3422917
13761c10b83c6
1437c107997b5
151bbe8a849c1
hexefdd51d4a3

1030210311331 has 2 divisors, whose sum is σ = 1030210311332. Its totient is φ = 1030210311330.

The previous prime is 1030210311313. The next prime is 1030210311343. The reversal of 1030210311331 is 1331130120301.

Together with previous prime (1030210311313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1030210311331 - 29 = 1030210310819 is a prime.

It is a super-2 number, since 2×10302103113312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1030210311299 and 1030210311308.

It is not a weakly prime, because it can be changed into another prime (1030210311311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515105155665 + 515105155666.

It is an arithmetic number, because the mean of its divisors is an integer number (515105155666).

Almost surely, 21030210311331 is an apocalyptic number.

1030210311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030210311331 is an equidigital number, since it uses as much as digits as its factorization.

1030210311331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1030210311331 its reverse (1331130120301), we get a palindrome (2361340431632).

The spelling of 1030210311331 in words is "one trillion, thirty billion, two hundred ten million, three hundred eleven thousand, three hundred thirty-one".