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10302103131 = 33434034377
BaseRepresentation
bin10011001100000110…
…11001111001011011
3222120222020001201020
421212003121321123
5132044314300011
64422133453523
7513203301045
oct114603317133
928528201636
1010302103131
1144072a5621
121bb61a12a3
13c82473618
146da322a95
15404685006
hex2660d9e5b

10302103131 has 4 divisors (see below), whose sum is σ = 13736137512. Its totient is φ = 6868068752.

The previous prime is 10302103129. The next prime is 10302103243. The reversal of 10302103131 is 13130120301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10302103131 - 21 = 10302103129 is a prime.

It is a super-2 number, since 2×103021031312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10302103131.

It is not an unprimeable number, because it can be changed into a prime (10302105131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1717017186 + ... + 1717017191.

It is an arithmetic number, because the mean of its divisors is an integer number (3434034378).

Almost surely, 210302103131 is an apocalyptic number.

10302103131 is a deficient number, since it is larger than the sum of its proper divisors (3434034381).

10302103131 is an equidigital number, since it uses as much as digits as its factorization.

10302103131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3434034380.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10302103131 its reverse (13130120301), we get a palindrome (23432223432).

The spelling of 10302103131 in words is "ten billion, three hundred two million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 3 3434034377 10302103131