Base | Representation |
---|---|
bin | 101111111110010001… |
… | …0101111000111000001 |
3 | 100211220201120211010001 |
4 | 1133330202233013001 |
5 | 3141441412241342 |
6 | 115154410040001 |
7 | 10304650566016 |
oct | 1377442570701 |
9 | 324821524101 |
10 | 103021212097 |
11 | 3a766874501 |
12 | 17b71719001 |
13 | 993a70cccb |
14 | 4db43c970d |
15 | 2a2e5bd8b7 |
hex | 17fc8af1c1 |
103021212097 has 2 divisors, whose sum is σ = 103021212098. Its totient is φ = 103021212096.
The previous prime is 103021212089. The next prime is 103021212103. The reversal of 103021212097 is 790212120301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74581425216 + 28439786881 = 273096^2 + 168641^2 .
It is a cyclic number.
It is not a de Polignac number, because 103021212097 - 23 = 103021212089 is a prime.
It is a super-2 number, since 2×1030212120972 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103021212017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51510606048 + 51510606049.
It is an arithmetic number, because the mean of its divisors is an integer number (51510606049).
Almost surely, 2103021212097 is an apocalyptic number.
It is an amenable number.
103021212097 is a deficient number, since it is larger than the sum of its proper divisors (1).
103021212097 is an equidigital number, since it uses as much as digits as its factorization.
103021212097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 103021212097 its reverse (790212120301), we get a palindrome (893233332398).
The spelling of 103021212097 in words is "one hundred three billion, twenty-one million, two hundred twelve thousand, ninety-seven".
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