Base | Representation |
---|---|
bin | 10111011011001010101110… |
… | …011111101101101100011011 |
3 | 111111202210211020010201012201 |
4 | 113123022232133231230123 |
5 | 102000403040324023232 |
6 | 1003035354235351031 |
7 | 30462044344562611 |
oct | 2733125637555433 |
9 | 444683736121181 |
10 | 103022013111067 |
11 | 2a90a432694026 |
12 | b67a4338b2477 |
13 | 4563c1b43874b |
14 | 1b624134dd6b1 |
15 | bd9c8b881be7 |
hex | 5db2ae7edb1b |
103022013111067 has 2 divisors, whose sum is σ = 103022013111068. Its totient is φ = 103022013111066.
The previous prime is 103022013111037. The next prime is 103022013111091. The reversal of 103022013111067 is 760111310220301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103022013111067 is a prime.
It is a super-2 number, since 2×1030220131110672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103022013111007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51511006555533 + 51511006555534.
It is an arithmetic number, because the mean of its divisors is an integer number (51511006555534).
Almost surely, 2103022013111067 is an apocalyptic number.
103022013111067 is a deficient number, since it is larger than the sum of its proper divisors (1).
103022013111067 is an equidigital number, since it uses as much as digits as its factorization.
103022013111067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 103022013111067 its reverse (760111310220301), we get a palindrome (863133323331368).
The spelling of 103022013111067 in words is "one hundred three trillion, twenty-two billion, thirteen million, one hundred eleven thousand, sixty-seven".
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