Base | Representation |
---|---|
bin | 101111111110010101… |
… | …0000011100111111011 |
3 | 100211220212012022112101 |
4 | 1133330222003213323 |
5 | 3141442410144011 |
6 | 115154515124231 |
7 | 10305003110614 |
oct | 1377452034773 |
9 | 324825168471 |
10 | 103023131131 |
11 | 3a767965288 |
12 | 17b722a3677 |
13 | 993ac3262b |
14 | 4db4768c0b |
15 | 2a2e84c2c1 |
hex | 17fca839fb |
103023131131 has 2 divisors, whose sum is σ = 103023131132. Its totient is φ = 103023131130.
The previous prime is 103023131117. The next prime is 103023131143. The reversal of 103023131131 is 131131320301.
It is a strong prime.
It is an emirp because it is prime and its reverse (131131320301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103023131131 - 215 = 103023098363 is a prime.
It is a super-2 number, since 2×1030231311312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103023131099 and 103023131108.
It is not a weakly prime, because it can be changed into another prime (103023131171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51511565565 + 51511565566.
It is an arithmetic number, because the mean of its divisors is an integer number (51511565566).
Almost surely, 2103023131131 is an apocalyptic number.
103023131131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103023131131 is an equidigital number, since it uses as much as digits as its factorization.
103023131131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 103023131131 its reverse (131131320301), we get a palindrome (234154451432).
The spelling of 103023131131 in words is "one hundred three billion, twenty-three million, one hundred thirty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •