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1030311303121 = 7517871370483
BaseRepresentation
bin11101111111000110101…
…01101101011111010001
310122111102011111011110101
432333203111231133101
5113340034143144441
62105152442532401
7134303034402112
oct16774325553721
93574364434411
101030311303121
11367a52963631
12147821207101
1376208cb8469
1437c1dd68209
151bc02883231
hexefe356d7d1

1030311303121 has 4 divisors (see below), whose sum is σ = 1030313425392. Its totient is φ = 1030309180852.

The previous prime is 1030311303079. The next prime is 1030311303143. The reversal of 1030311303121 is 1213031130301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1030311303121 - 211 = 1030311301073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1030311303181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66546 + ... + 1437028.

It is an arithmetic number, because the mean of its divisors is an integer number (257578356348).

Almost surely, 21030311303121 is an apocalyptic number.

It is an amenable number.

1030311303121 is a deficient number, since it is larger than the sum of its proper divisors (2122271).

1030311303121 is an equidigital number, since it uses as much as digits as its factorization.

1030311303121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2122270.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1030311303121 its reverse (1213031130301), we get a palindrome (2243342433422).

The spelling of 1030311303121 in words is "one trillion, thirty billion, three hundred eleven million, three hundred three thousand, one hundred twenty-one".

Divisors: 1 751787 1370483 1030311303121