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103032623113 = 760124490759
BaseRepresentation
bin101111111110100111…
…0010001000000001001
3100211221112001120002021
41133331032101000021
53142002322414423
6115155454404441
710305146563210
oct1377516210011
9324845046067
10103032623113
113a7722587a2
1217b75500721
13993cba6ba4
144db5b1a077
152a305c495d
hex17fd391009

103032623113 has 8 divisors (see below), whose sum is σ = 117947500160. Its totient is φ = 88166728800.

The previous prime is 103032623069. The next prime is 103032623131. The reversal of 103032623113 is 311326230301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103032623113 - 233 = 94442688521 is a prime.

It is a super-5 number, since 5×1030326231135 (a number of 56 digits) contains 55555 as substring. Note that it is a super-d number also for d = 4.

It is not an unprimeable number, because it can be changed into a prime (103032623143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12241173 + ... + 12249586.

It is an arithmetic number, because the mean of its divisors is an integer number (14743437520).

Almost surely, 2103032623113 is an apocalyptic number.

It is an amenable number.

103032623113 is a deficient number, since it is larger than the sum of its proper divisors (14914877047).

103032623113 is an equidigital number, since it uses as much as digits as its factorization.

103032623113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24491367.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 103032623113 its reverse (311326230301), we get a palindrome (414358853414).

The spelling of 103032623113 in words is "one hundred three billion, thirty-two million, six hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 7 601 4207 24490759 171435313 14718946159 103032623113