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10303372573121 is a prime number
BaseRepresentation
bin1001010111101111000011…
…0111001011100111000001
31100110222210202020202011002
42111323300313023213001
52322302301334314441
633525145400101345
72112252114563435
oct225736067134701
940428722222132
1010303372573121
1133126aa233431
1211a4a42764855
135997b08c9214
1427898613c9c5
1512d03373cb9b
hex95ef0dcb9c1

10303372573121 has 2 divisors, whose sum is σ = 10303372573122. Its totient is φ = 10303372573120.

The previous prime is 10303372573069. The next prime is 10303372573129. The reversal of 10303372573121 is 12137527330301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8656770333121 + 1646602240000 = 2942239^2 + 1283200^2 .

It is a cyclic number.

It is not a de Polignac number, because 10303372573121 - 218 = 10303372310977 is a prime.

It is a super-3 number, since 3×103033725731213 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10303372573129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5151686286560 + 5151686286561.

It is an arithmetic number, because the mean of its divisors is an integer number (5151686286561).

Almost surely, 210303372573121 is an apocalyptic number.

It is an amenable number.

10303372573121 is a deficient number, since it is larger than the sum of its proper divisors (1).

10303372573121 is an equidigital number, since it uses as much as digits as its factorization.

10303372573121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 79380, while the sum is 38.

The spelling of 10303372573121 in words is "ten trillion, three hundred three billion, three hundred seventy-two million, five hundred seventy-three thousand, one hundred twenty-one".