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1031000324131 is a prime number
BaseRepresentation
bin11110000000011000110…
…10000111100000100011
310122120012012000001121001
433000030122013200203
5113342442040333011
62105345055012431
7134326102105531
oct17001432074043
93576165001531
101031000324131
11368276894288
12147993b0a117
13762b89824bb
1437c87685151
151bc430d77c1
hexf00c687823

1031000324131 has 2 divisors, whose sum is σ = 1031000324132. Its totient is φ = 1031000324130.

The previous prime is 1031000324111. The next prime is 1031000324153. The reversal of 1031000324131 is 1314230001301.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1031000324131 - 211 = 1031000322083 is a prime.

It is a super-2 number, since 2×10310003241312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1031000324099 and 1031000324108.

It is not a weakly prime, because it can be changed into another prime (1031000324111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515500162065 + 515500162066.

It is an arithmetic number, because the mean of its divisors is an integer number (515500162066).

Almost surely, 21031000324131 is an apocalyptic number.

1031000324131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031000324131 is an equidigital number, since it uses as much as digits as its factorization.

1031000324131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1031000324131 its reverse (1314230001301), we get a palindrome (2345230325432).

The spelling of 1031000324131 in words is "one trillion, thirty-one billion, three hundred twenty-four thousand, one hundred thirty-one".