Search a number
-
+
103100132131 = 162676337993
BaseRepresentation
bin110000000000100111…
…1110010101100100011
3100212010020002101001021
41200001033302230203
53142122113212011
6115210305350311
710306626443413
oct1400117625443
9325106071037
10103100132131
113a7a7378277
1217b94038397
139950b82959
144dc0a90643
152a364ac471
hex18013f2b23

103100132131 has 4 divisors (see below), whose sum is σ = 103106486392. Its totient is φ = 103093777872.

The previous prime is 103100132123. The next prime is 103100132141. The reversal of 103100132131 is 131231001301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103100132131 - 23 = 103100132123 is a prime.

It is a super-2 number, since 2×1031001321312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103100132141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3152730 + ... + 3185263.

It is an arithmetic number, because the mean of its divisors is an integer number (25776621598).

Almost surely, 2103100132131 is an apocalyptic number.

103100132131 is a deficient number, since it is larger than the sum of its proper divisors (6354261).

103100132131 is an equidigital number, since it uses as much as digits as its factorization.

103100132131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6354260.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 103100132131 its reverse (131231001301), we get a palindrome (234331133432).

The spelling of 103100132131 in words is "one hundred three billion, one hundred million, one hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 16267 6337993 103100132131