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103103132113 = 831242206411
BaseRepresentation
bin110000000000101101…
…1001111000111010001
3100212010102201210020201
41200001123033013101
53142123400211423
6115210453535201
710306664106622
oct1400133170721
9325112653221
10103103132113
113a7a90371a3
1217b95044501
1399516932a7
144dc1231a49
152a368a12ad
hex18016cf1d1

103103132113 has 4 divisors (see below), whose sum is σ = 104345338608. Its totient is φ = 101860925620.

The previous prime is 103103132101. The next prime is 103103132117. The reversal of 103103132113 is 311231301301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311231301301 = 674645243303.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103103132113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103103132117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 621103123 + ... + 621103288.

It is an arithmetic number, because the mean of its divisors is an integer number (26086334652).

Almost surely, 2103103132113 is an apocalyptic number.

It is an amenable number.

103103132113 is a deficient number, since it is larger than the sum of its proper divisors (1242206495).

103103132113 is an equidigital number, since it uses as much as digits as its factorization.

103103132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1242206494.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 103103132113 its reverse (311231301301), we get a palindrome (414334433414).

The spelling of 103103132113 in words is "one hundred three billion, one hundred three million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 83 1242206411 103103132113