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10311020123 = 73141246851
BaseRepresentation
bin10011001101001010…
…11010111001011011
3222121121000002112012
421212211122321123
5132104110120443
64423052540135
7513342140105
oct114645327133
928547002465
1010311020123
114411336038
121bb918164b
13c84276251
146db5a4575
15405347118
hex26695ae5b

10311020123 has 4 divisors (see below), whose sum is σ = 10452267048. Its totient is φ = 10169773200.

The previous prime is 10311020119. The next prime is 10311020173. The reversal of 10311020123 is 32102011301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10311020123 - 22 = 10311020119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10311020098 and 10311020107.

It is not an unprimeable number, because it can be changed into a prime (10311020113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70623353 + ... + 70623498.

It is an arithmetic number, because the mean of its divisors is an integer number (2613066762).

Almost surely, 210311020123 is an apocalyptic number.

10311020123 is a deficient number, since it is larger than the sum of its proper divisors (141246925).

10311020123 is an equidigital number, since it uses as much as digits as its factorization.

10311020123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141246924.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 10311020123 its reverse (32102011301), we get a palindrome (42413031424).

The spelling of 10311020123 in words is "ten billion, three hundred eleven million, twenty thousand, one hundred twenty-three".

Divisors: 1 73 141246851 10311020123