10311023113 has 4 divisors (see below), whose sum is σ = 10853708560. Its totient is φ = 9768337668.

The previous prime is 10311023111. The next prime is 10311023117. The reversal of 10311023113 is 31132011301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31132011301 = 61 ⋅510360841.

It is a cyclic number.

It is not a de Polignac number, because 10311023113 - 2¹ = 10311023111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10311023111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271342695 + ... + 271342732.

It is an arithmetic number, because the mean of its divisors is an integer number (2713427140).

Almost surely, 2^10311023113 is an apocalyptic number.

It is an amenable number.

10311023113 is a deficient number, since it is larger than the sum of its proper divisors (542685447).

10311023113 is an equidigital number, since it uses as much as digits as its factorization.

10311023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 542685446.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10311023113 its reverse (31132011301), we get a palindrome (41443034414).

It can be divided in two parts, 1031 and 1023113, that added together give a square (1024144 = 1012²).

The spelling of 10311023113 in words is "ten billion, three hundred eleven million, twenty-three thousand, one hundred thirteen".