Base | Representation |
---|---|
bin | 10111011100011101101000… |
… | …011001001101010110010001 |
3 | 111112002022121001120221200122 |
4 | 113130131220121031112101 |
5 | 102003332343004020214 |
6 | 1003144315344400025 |
7 | 30501345323040521 |
oct | 2734355031152621 |
9 | 445068531527618 |
10 | 103111031313809 |
11 | 2a944163094322 |
12 | b693737916015 |
13 | 456c436a24bac |
14 | 1b66859c6b681 |
15 | bdc24b92588e |
hex | 5dc76864d591 |
103111031313809 has 2 divisors, whose sum is σ = 103111031313810. Its totient is φ = 103111031313808.
The previous prime is 103111031313791. The next prime is 103111031313821. The reversal of 103111031313809 is 908313130111301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87555264267409 + 15555767046400 = 9357097^2 + 3944080^2 .
It is a cyclic number.
It is not a de Polignac number, because 103111031313809 - 220 = 103111030265233 is a prime.
It is not a weakly prime, because it can be changed into another prime (103111031333809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51555515656904 + 51555515656905.
It is an arithmetic number, because the mean of its divisors is an integer number (51555515656905).
Almost surely, 2103111031313809 is an apocalyptic number.
It is an amenable number.
103111031313809 is a deficient number, since it is larger than the sum of its proper divisors (1).
103111031313809 is an equidigital number, since it uses as much as digits as its factorization.
103111031313809 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 103111031313809 in words is "one hundred three trillion, one hundred eleven billion, thirty-one million, three hundred thirteen thousand, eight hundred nine".
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