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103113020001 = 334371006667
BaseRepresentation
bin110000000001000000…
…0111101001001100001
3100212011010100010212210
41200002000331021201
53142133413120001
6115211445512333
710310144131365
oct1400200751141
9325133303783
10103113020001
113a803680102
1217b984126a9
139953745b04
144dc26872a5
152a376a5dd6
hex180203d261

103113020001 has 4 divisors (see below), whose sum is σ = 137484026672. Its totient is φ = 68742013332.

The previous prime is 103113019993. The next prime is 103113020011. The reversal of 103113020001 is 100020311301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 103113020001 - 23 = 103113019993 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (103113020011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17185503331 + ... + 17185503336.

It is an arithmetic number, because the mean of its divisors is an integer number (34371006668).

Almost surely, 2103113020001 is an apocalyptic number.

It is an amenable number.

103113020001 is a deficient number, since it is larger than the sum of its proper divisors (34371006671).

103113020001 is an equidigital number, since it uses as much as digits as its factorization.

103113020001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34371006670.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 103113020001 its reverse (100020311301), we get a palindrome (203133331302).

The spelling of 103113020001 in words is "one hundred three billion, one hundred thirteen million, twenty thousand, one".

Divisors: 1 3 34371006667 103113020001