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103121011249 is a prime number
BaseRepresentation
bin110000000001001111…
…1011100001000110001
3100212011200101010210221
41200002133130020301
53142142434324444
6115212333053041
710310302063444
oct1400237341061
9325150333727
10103121011249
113a808139043
1217b9b027181
1399552b3269
144dc376765b
152a38233a84
hex18027dc231

103121011249 has 2 divisors, whose sum is σ = 103121011250. Its totient is φ = 103121011248.

The previous prime is 103121011199. The next prime is 103121011261. The reversal of 103121011249 is 942110121301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65351809600 + 37769201649 = 255640^2 + 194343^2 .

It is an emirp because it is prime and its reverse (942110121301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103121011249 - 213 = 103121003057 is a prime.

It is a super-2 number, since 2×1031210112492 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103121011349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560505624 + 51560505625.

It is an arithmetic number, because the mean of its divisors is an integer number (51560505625).

Almost surely, 2103121011249 is an apocalyptic number.

It is an amenable number.

103121011249 is a deficient number, since it is larger than the sum of its proper divisors (1).

103121011249 is an equidigital number, since it uses as much as digits as its factorization.

103121011249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 103121011249 in words is "one hundred three billion, one hundred twenty-one million, eleven thousand, two hundred forty-nine".