Base | Representation |
---|---|
bin | 11110000000110001111… |
… | …01111001101000001011 |
3 | 10122120201212111002011001 |
4 | 33000120331321220023 |
5 | 113343410010443201 |
6 | 2105422023115431 |
7 | 134334241065445 |
oct | 17003075715013 |
9 | 3576655432131 |
10 | 1031211031051 |
11 | 36837481a533 |
12 | 147a325a2b77 |
13 | 76320518056 |
14 | 37ca7653495 |
15 | 1bc56859301 |
hex | f018f79a0b |
1031211031051 has 2 divisors, whose sum is σ = 1031211031052. Its totient is φ = 1031211031050.
The previous prime is 1031211031027. The next prime is 1031211031061. The reversal of 1031211031051 is 1501301121301.
1031211031051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1031211031051 - 211 = 1031211029003 is a prime.
It is a super-2 number, since 2×10312110310512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1031211031061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515605515525 + 515605515526.
It is an arithmetic number, because the mean of its divisors is an integer number (515605515526).
Almost surely, 21031211031051 is an apocalyptic number.
1031211031051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031211031051 is an equidigital number, since it uses as much as digits as its factorization.
1031211031051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 19.
Adding to 1031211031051 its reverse (1501301121301), we get a palindrome (2532512152352).
The spelling of 1031211031051 in words is "one trillion, thirty-one billion, two hundred eleven million, thirty-one thousand, fifty-one".
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