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103121213123233 is a prime number
BaseRepresentation
bin10111011100100111000111…
…010001101110101010100001
3111112010021212122110110110101
4113130213013101232222201
5102004014221024420413
61003153121544102401
730502155536015224
oct2734470721565241
9445107778413411
10103121213123233
112a948508497458
12b6956b9764a01
13457039a29a9b6
141b671441d95bb
15bdc645747edd
hex5dc9c746eaa1

103121213123233 has 2 divisors, whose sum is σ = 103121213123234. Its totient is φ = 103121213123232.

The previous prime is 103121213123209. The next prime is 103121213123249. The reversal of 103121213123233 is 332321312121301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85851769578129 + 17269443545104 = 9265623^2 + 4155652^2 .

It is an emirp because it is prime and its reverse (332321312121301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103121213123233 is a prime.

It is not a weakly prime, because it can be changed into another prime (103121213123263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560606561616 + 51560606561617.

It is an arithmetic number, because the mean of its divisors is an integer number (51560606561617).

Almost surely, 2103121213123233 is an apocalyptic number.

It is an amenable number.

103121213123233 is a deficient number, since it is larger than the sum of its proper divisors (1).

103121213123233 is an equidigital number, since it uses as much as digits as its factorization.

103121213123233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 103121213123233 its reverse (332321312121301), we get a palindrome (435442525244534).

The spelling of 103121213123233 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred thirteen million, one hundred twenty-three thousand, two hundred thirty-three".