Base | Representation |
---|---|
bin | 10111011100100111001101… |
… | …101001011110110011001010 |
3 | 111112010022011002121000122201 |
4 | 113130213031221132303022 |
5 | 102004014430410404002 |
6 | 1003153140323110414 |
7 | 30502161304404214 |
oct | 2734471551366312 |
9 | 445108132530581 |
10 | 103121320013002 |
11 | 2a948562864305 |
12 | b69572951240a |
13 | 45703b6484495 |
14 | 1b671544a15b4 |
15 | bdc64ed0e087 |
hex | 5dc9cda5ecca |
103121320013002 has 4 divisors (see below), whose sum is σ = 154681980019506. Its totient is φ = 51560660006500.
The previous prime is 103121320012981. The next prime is 103121320013009. The reversal of 103121320013002 is 200310023121301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 101863178667441 + 1258141345561 = 10092729^2 + 1121669^2 .
It is not an unprimeable number, because it can be changed into a prime (103121320013009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25780330003249 + ... + 25780330003252.
Almost surely, 2103121320013002 is an apocalyptic number.
103121320013002 is a deficient number, since it is larger than the sum of its proper divisors (51560660006504).
103121320013002 is an equidigital number, since it uses as much as digits as its factorization.
103121320013002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51560660006503.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 103121320013002 its reverse (200310023121301), we get a palindrome (303431343134303).
The spelling of 103121320013002 in words is "one hundred three trillion, one hundred twenty-one billion, three hundred twenty million, thirteen thousand, two".
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