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10312303147 is a prime number
BaseRepresentation
bin10011001101010100…
…10100001000101011
3222121200102021111121
421212222110020223
5132104422200042
64423140240111
7513356062516
oct114652241053
928550367447
1010312303147
114412031a93
121bb96a0037
13c84605233
146db819d7d
154054ec367
hex266a9422b

10312303147 has 2 divisors, whose sum is σ = 10312303148. Its totient is φ = 10312303146.

The previous prime is 10312303103. The next prime is 10312303151. The reversal of 10312303147 is 74130321301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10312303147 - 215 = 10312270379 is a prime.

It is a super-2 number, since 2×103123031472 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10312303187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156151573 + 5156151574.

It is an arithmetic number, because the mean of its divisors is an integer number (5156151574).

Almost surely, 210312303147 is an apocalyptic number.

10312303147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312303147 is an equidigital number, since it uses as much as digits as its factorization.

10312303147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 10312303147 its reverse (74130321301), we get a palindrome (84442624448).

The spelling of 10312303147 in words is "ten billion, three hundred twelve million, three hundred three thousand, one hundred forty-seven".