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10312331222113 = 19153991262943
BaseRepresentation
bin1001011000010000011011…
…0101101101110001100001
31100111211221002112021020121
42112010012311231301201
52322424123243101423
633533230343040241
72113020116051554
oct226040665556141
940454832467217
1010312331222113
113316487150a78
1211a6722a40081
1359a5aa92ba5b
14279195c6c69b
1512d3a9e9c45d
hex96106d6dc61

10312331222113 has 4 divisors (see below), whose sum is σ = 10366322485248. Its totient is φ = 10258339958980.

The previous prime is 10312331222057. The next prime is 10312331222119. The reversal of 10312331222113 is 31122213321301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10312331222113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10312331222119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26995631281 + ... + 26995631662.

It is an arithmetic number, because the mean of its divisors is an integer number (2591580621312).

Almost surely, 210312331222113 is an apocalyptic number.

It is an amenable number.

10312331222113 is a deficient number, since it is larger than the sum of its proper divisors (53991263135).

10312331222113 is an equidigital number, since it uses as much as digits as its factorization.

10312331222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53991263134.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 10312331222113 its reverse (31122213321301), we get a palindrome (41434544543414).

The spelling of 10312331222113 in words is "ten trillion, three hundred twelve billion, three hundred thirty-one million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 191 53991262943 10312331222113