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10312413132 = 2237122766823
BaseRepresentation
bin10011001101010101…
…01110111111001100
3222121200121212101010
421212222232333030
5132104434210012
64423142445220
7513360031260
oct114652567714
928550555333
1010312413132
1144120a768a
121bb9733810
13c84643308
146db8480a0
1540551ec3c
hex266aaefcc

10312413132 has 24 divisors (see below), whose sum is σ = 27499768576. Its totient is φ = 2946403728.

The previous prime is 10312413131. The next prime is 10312413157. The reversal of 10312413132 is 23131421301.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 10312413099 and 10312413108.

It is not an unprimeable number, because it can be changed into a prime (10312413131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61383328 + ... + 61383495.

Almost surely, 210312413132 is an apocalyptic number.

10312413132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

10312413132 is an abundant number, since it is smaller than the sum of its proper divisors (17187355444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10312413132 is a wasteful number, since it uses less digits than its factorization.

10312413132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122766837 (or 122766835 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10312413132 its reverse (23131421301), we get a palindrome (33443834433).

The spelling of 10312413132 in words is "ten billion, three hundred twelve million, four hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 7 12 14 21 28 42 84 122766823 245533646 368300469 491067292 736600938 859367761 1473201876 1718735522 2578103283 3437471044 5156206566 10312413132