Base | Representation |
---|---|
bin | 1001011000010000110110… |
… | …1001101100110101001011 |
3 | 1100111212020001120211220201 |
4 | 2112010031221230311023 |
5 | 2322424342022404120 |
6 | 33533245544433031 |
7 | 2113023004364341 |
oct | 226041551546513 |
9 | 40455201524821 |
10 | 10312445513035 |
11 | 3316535713486 |
12 | 11a6755178777 |
13 | 59a5c8507213 |
14 | 2791a70dd991 |
15 | 12d3b502640a |
hex | 9610da6cd4b |
10312445513035 has 16 divisors (see below), whose sum is σ = 12807935265600. Its totient is φ = 7961568366976.
The previous prime is 10312445512979. The next prime is 10312445513077. The reversal of 10312445513035 is 53031554421301.
It is a cyclic number.
It is not a de Polignac number, because 10312445513035 - 217 = 10312445381963 is a prime.
It is a super-2 number, since 2×103124455130352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10312445512985 and 10312445513003.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17144344 + ... + 17735653.
It is an arithmetic number, because the mean of its divisors is an integer number (800495954100).
Almost surely, 210312445513035 is an apocalyptic number.
10312445513035 is a deficient number, since it is larger than the sum of its proper divisors (2495489752565).
10312445513035 is a wasteful number, since it uses less digits than its factorization.
10312445513035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34882070.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 10312445513035 its reverse (53031554421301), we get a palindrome (63343999934336).
The spelling of 10312445513035 in words is "ten trillion, three hundred twelve billion, four hundred forty-five million, five hundred thirteen thousand, thirty-five".
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