Base | Representation |
---|---|
bin | 1001011000010001001101… |
… | …1110011011110101100111 |
3 | 1100111212110212110000222121 |
4 | 2112010103132123311213 |
5 | 2322430042031120033 |
6 | 33533303355010411 |
7 | 2113025302041430 |
oct | 226042336336547 |
9 | 40455425400877 |
10 | 10312543223143 |
11 | 3316585890537 |
12 | 11a6781a39a07 |
13 | 59a612828655 |
14 | 2791b6096487 |
15 | 12d3bd8c762d |
hex | 9611379bd67 |
10312543223143 has 32 divisors (see below), whose sum is σ = 12418374205440. Its totient is φ = 8365791702240.
The previous prime is 10312543223077. The next prime is 10312543223161. The reversal of 10312543223143 is 34132234521301.
It is not a de Polignac number, because 10312543223143 - 225 = 10312509668711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10312543223099 and 10312543223108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10312541223143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 902781930 + ... + 902793352.
It is an arithmetic number, because the mean of its divisors is an integer number (388074193920).
Almost surely, 210312543223143 is an apocalyptic number.
10312543223143 is a deficient number, since it is larger than the sum of its proper divisors (2105830982297).
10312543223143 is a wasteful number, since it uses less digits than its factorization.
10312543223143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17587.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 10312543223143 its reverse (34132234521301), we get a palindrome (44444777744444).
The spelling of 10312543223143 in words is "ten trillion, three hundred twelve billion, five hundred forty-three million, two hundred twenty-three thousand, one hundred forty-three".
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