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1031300220017 is a prime number
BaseRepresentation
bin11110000000111100100…
…10001000010001110001
310122120222002022100102002
433000132102020101301
5113344100324020032
62105434530503345
7134336403142544
oct17003622102161
93576862270362
101031300220017
113684100a7521
12147a58434b55
1376335b44aa2
1437cb542c85b
151bc5e5c5862
hexf01e488471

1031300220017 has 2 divisors, whose sum is σ = 1031300220018. Its totient is φ = 1031300220016.

The previous prime is 1031300219933. The next prime is 1031300220029. The reversal of 1031300220017 is 7100220031301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1024611597361 + 6688622656 = 1012231^2 + 81784^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031300220017 - 212 = 1031300215921 is a prime.

It is a super-2 number, since 2×10313002200172 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1031300220917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515650110008 + 515650110009.

It is an arithmetic number, because the mean of its divisors is an integer number (515650110009).

Almost surely, 21031300220017 is an apocalyptic number.

It is an amenable number.

1031300220017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031300220017 is an equidigital number, since it uses as much as digits as its factorization.

1031300220017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 1031300220017 its reverse (7100220031301), we get a palindrome (8131520251318).

The spelling of 1031300220017 in words is "one trillion, thirty-one billion, three hundred million, two hundred twenty thousand, seventeen".