Base | Representation |
---|---|
bin | 10011001101011010… |
… | …01000110111100011 |
3 | 222121201210212222101 |
4 | 21212231020313203 |
5 | 132110114342202 |
6 | 4423204151231 |
7 | 513365265001 |
oct | 114655106743 |
9 | 28551725871 |
10 | 10313043427 |
11 | 4412498195 |
12 | 1bb9998517 |
13 | c8480417b |
14 | 6db96da71 |
15 | 4055e6887 |
hex | 266b48de3 |
10313043427 has 2 divisors, whose sum is σ = 10313043428. Its totient is φ = 10313043426.
The previous prime is 10313043409. The next prime is 10313043449. The reversal of 10313043427 is 72434031301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10313043427 - 211 = 10313041379 is a prime.
It is a super-3 number, since 3×103130434273 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10313043395 and 10313043404.
It is not a weakly prime, because it can be changed into another prime (10313043227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156521713 + 5156521714.
It is an arithmetic number, because the mean of its divisors is an integer number (5156521714).
Almost surely, 210313043427 is an apocalyptic number.
10313043427 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313043427 is an equidigital number, since it uses as much as digits as its factorization.
10313043427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 10313043427 its reverse (72434031301), we get a palindrome (82747074728).
The spelling of 10313043427 in words is "ten billion, three hundred thirteen million, forty-three thousand, four hundred twenty-seven".
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