103131010121113 has 16 divisors (see below), whose sum is σ = 112448194048960. Its totient is φ = 94017234413376.

The previous prime is 103131010120993. The next prime is 103131010121149. The reversal of 103131010121113 is 311121010131301.

It is a cyclic number.

It is not a de Polignac number, because 103131010121113 - 2³³ = 103122420186521 is a prime.

It is a super-2 number, since 2×103131010121113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103131010521113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 118101195 + ... + 118971232.

It is an arithmetic number, because the mean of its divisors is an integer number (7028012128060).

Almost surely, 2^{103131010121113} is an apocalyptic number.

103131010121113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

103131010121113 is a deficient number, since it is larger than the sum of its proper divisors (9317183927847).

103131010121113 is a wasteful number, since it uses less digits than its factorization.

103131010121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237072856.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 103131010121113 its reverse (311121010131301), we get a palindrome (414252020252414).

The spelling of 103131010121113 in words is "one hundred three trillion, one hundred thirty-one billion, ten million, one hundred twenty-one thousand, one hundred thirteen".