Base | Representation |
---|---|
bin | 110000000001100011… |
… | …0010110101000100011 |
3 | 100212012101120102001111 |
4 | 1200003012112220203 |
5 | 3142203042243243 |
6 | 115213335444151 |
7 | 10310454561256 |
oct | 1400306265043 |
9 | 325171512044 |
10 | 103131212323 |
11 | 3a812976287 |
12 | 17ba2526657 |
13 | 99574454b9 |
14 | 4dc4c6109d |
15 | 2a3909b39d |
hex | 1803196a23 |
103131212323 has 2 divisors, whose sum is σ = 103131212324. Its totient is φ = 103131212322.
The previous prime is 103131212293. The next prime is 103131212333. The reversal of 103131212323 is 323212131301.
It is a strong prime.
It is an emirp because it is prime and its reverse (323212131301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103131212323 - 233 = 94541277731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103131212294 and 103131212303.
It is not a weakly prime, because it can be changed into another prime (103131212333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565606161 + 51565606162.
It is an arithmetic number, because the mean of its divisors is an integer number (51565606162).
Almost surely, 2103131212323 is an apocalyptic number.
103131212323 is a deficient number, since it is larger than the sum of its proper divisors (1).
103131212323 is an equidigital number, since it uses as much as digits as its factorization.
103131212323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 103131212323 its reverse (323212131301), we get a palindrome (426343343624).
The spelling of 103131212323 in words is "one hundred three billion, one hundred thirty-one million, two hundred twelve thousand, three hundred twenty-three".
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