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10313130000000 = 27357343771
BaseRepresentation
bin1001011000010011011001…
…1100110011111010000000
31100111220222202120101111210
42112010312130303322000
52322432242240000000
633533441515410120
72113045655415222
oct226046634637200
940456882511453
1010313130000000
113316857027693
1211a6906453940
1359a6a72745a9
1427922dd9a412
1512d405182350
hex96136733e80

10313130000000 has 256 divisors, whose sum is σ = 34242826400640. Its totient is φ = 2750160000000.

The previous prime is 10313129999999. The next prime is 10313130000077. The reversal of 10313130000000 is 3131301.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29828115 + ... + 30171885.

Almost surely, 210313130000000 is an apocalyptic number.

10313130000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10313130000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17121413200320).

10313130000000 is an abundant number, since it is smaller than the sum of its proper divisors (23929696400640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10313130000000 is an frugal number, since it uses more digits than its factorization.

10313130000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 343823 (or 343781 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 10313130000000 its reverse (3131301), we get a palindrome (10313133131301).

The spelling of 10313130000000 in words is "ten trillion, three hundred thirteen billion, one hundred thirty million", and thus it is an aban number.