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1031313000323 is a prime number
BaseRepresentation
bin11110000000111110000…
…10111000011110000011
310122120222222100122200202
433000133002320132003
5113344112112002243
62105440104435415
7134336616602114
oct17003702703603
93576888318622
101031313000323
11368417336561
12147a60778b6b
137633869acb8
1437cb6dd820b
151bc6079c4b8
hexf01f0b8783

1031313000323 has 2 divisors, whose sum is σ = 1031313000324. Its totient is φ = 1031313000322.

The previous prime is 1031313000301. The next prime is 1031313000329. The reversal of 1031313000323 is 3230003131301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1031313000323 - 222 = 1031308806019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1031313000295 and 1031313000304.

It is not a weakly prime, because it can be changed into another prime (1031313000329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515656500161 + 515656500162.

It is an arithmetic number, because the mean of its divisors is an integer number (515656500162).

Almost surely, 21031313000323 is an apocalyptic number.

1031313000323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031313000323 is an equidigital number, since it uses as much as digits as its factorization.

1031313000323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 1031313000323 its reverse (3230003131301), we get a palindrome (4261316131624).

The spelling of 1031313000323 in words is "one trillion, thirty-one billion, three hundred thirteen million, three hundred twenty-three", and thus it is an aban number.