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1031314311403 = 1951528608053
BaseRepresentation
bin11110000000111110001…
…11111000100011101011
310122121000001211021011021
433000133013320203223
5113344112430431103
62105440152513311
7134336634002365
oct17003707704353
93577001737137
101031314311403
113684180515a2
12147a610ab837
1376338a3999c
1437cb7259d35
151bc6095abbd
hexf01f1f88eb

1031314311403 has 4 divisors (see below), whose sum is σ = 1031842921408. Its totient is φ = 1030785701400.

The previous prime is 1031314311389. The next prime is 1031314311449. The reversal of 1031314311403 is 3041134131301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1031314311403 - 25 = 1031314311371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1031314311473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264302076 + ... + 264305977.

It is an arithmetic number, because the mean of its divisors is an integer number (257960730352).

Almost surely, 21031314311403 is an apocalyptic number.

1031314311403 is a deficient number, since it is larger than the sum of its proper divisors (528610005).

1031314311403 is an equidigital number, since it uses as much as digits as its factorization.

1031314311403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 528610004.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1031314311403 its reverse (3041134131301), we get a palindrome (4072448442704).

The spelling of 1031314311403 in words is "one trillion, thirty-one billion, three hundred fourteen million, three hundred eleven thousand, four hundred three".

Divisors: 1 1951 528608053 1031314311403