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1031315806897 is a prime number
BaseRepresentation
bin11110000000111110011…
…01100101101010110001
310122121000011122020120221
433000133031211222301
5113344113321310042
62105440244533041
7134336652501415
oct17003715455261
93577004566527
101031315806897
11368418983142
12147a616b1181
13763391415ac
1437cb7528d45
151bc60b53d67
hexf01f365ab1

1031315806897 has 2 divisors, whose sum is σ = 1031315806898. Its totient is φ = 1031315806896.

The previous prime is 1031315806837. The next prime is 1031315806903. The reversal of 1031315806897 is 7986085131301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 991221351201 + 40094455696 = 995601^2 + 200236^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1031315806897 is a prime.

It is a super-4 number, since 4×10313158068974 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1031315806817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515657903448 + 515657903449.

It is an arithmetic number, because the mean of its divisors is an integer number (515657903449).

Almost surely, 21031315806897 is an apocalyptic number.

It is an amenable number.

1031315806897 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031315806897 is an equidigital number, since it uses as much as digits as its factorization.

1031315806897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1088640, while the sum is 52.

The spelling of 1031315806897 in words is "one trillion, thirty-one billion, three hundred fifteen million, eight hundred six thousand, eight hundred ninety-seven".