Base | Representation |
---|---|
bin | 1001011000010100000101… |
… | …0110111100011010010011 |
3 | 1100111221110111221022212211 |
4 | 2112011001112330122103 |
5 | 2322433131112330342 |
6 | 33533512014132551 |
7 | 2113053340115053 |
oct | 226050126743223 |
9 | 40457414838784 |
10 | 10313313011347 |
11 | 3316940366835 |
12 | 11a69577b1157 |
13 | 59a706161028 |
14 | 27924a3d9563 |
15 | 12d416282c17 |
hex | 961415bc693 |
10313313011347 has 2 divisors, whose sum is σ = 10313313011348. Its totient is φ = 10313313011346.
The previous prime is 10313313011291. The next prime is 10313313011371. The reversal of 10313313011347 is 74311031331301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10313313011347 is a prime.
It is not a weakly prime, because it can be changed into another prime (10313313011387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156656505673 + 5156656505674.
It is an arithmetic number, because the mean of its divisors is an integer number (5156656505674).
Almost surely, 210313313011347 is an apocalyptic number.
10313313011347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313313011347 is an equidigital number, since it uses as much as digits as its factorization.
10313313011347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 10313313011347 its reverse (74311031331301), we get a palindrome (84624344342648).
The spelling of 10313313011347 in words is "ten trillion, three hundred thirteen billion, three hundred thirteen million, eleven thousand, three hundred forty-seven".
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