Base | Representation |
---|---|
bin | 10111011100111000111010… |
… | …100010010111101100110010 |
3 | 111112012010012201002112011001 |
4 | 113130320322202113230302 |
5 | 102004322342121002032 |
6 | 1003210002331112214 |
7 | 30503433306023641 |
oct | 2734707242275462 |
9 | 445163181075131 |
10 | 103140326734642 |
11 | 2a95562664061a |
12 | b6993528a266a |
13 | 4572125136532 |
14 | 1b680388a9358 |
15 | bdcdb37753e7 |
hex | 5dce3a897b32 |
103140326734642 has 4 divisors (see below), whose sum is σ = 154710490101966. Its totient is φ = 51570163367320.
The previous prime is 103140326734639. The next prime is 103140326734673. The reversal of 103140326734642 is 246437623041301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 91767184271361 + 11373142463281 = 9579519^2 + 3372409^2 .
It is a junction number, because it is equal to n+sod(n) for n = 103140326734592 and 103140326734601.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25785081683659 + ... + 25785081683662.
Almost surely, 2103140326734642 is an apocalyptic number.
103140326734642 is a deficient number, since it is larger than the sum of its proper divisors (51570163367324).
103140326734642 is an equidigital number, since it uses as much as digits as its factorization.
103140326734642 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51570163367323.
The product of its (nonzero) digits is 1741824, while the sum is 46.
Adding to 103140326734642 its reverse (246437623041301), we get a palindrome (349577949775943).
The spelling of 103140326734642 in words is "one hundred three trillion, one hundred forty billion, three hundred twenty-six million, seven hundred thirty-four thousand, six hundred forty-two".
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