Base | Representation |
---|---|
bin | 11110000001001001111… |
… | …01010110010111100110 |
3 | 10122121020220001012012120 |
4 | 33000210331112113212 |
5 | 113344313011310342 |
6 | 2105454011130410 |
7 | 134342233105416 |
oct | 17004475262746 |
9 | 3577226035176 |
10 | 1031412213222 |
11 | 36846833a696 |
12 | 147a89a43a06 |
13 | 763530c7461 |
14 | 37cc6262646 |
15 | 1bc69348aec |
hex | f024f565e6 |
1031412213222 has 32 divisors (see below), whose sum is σ = 2067747264000. Its totient is φ = 342983843328.
The previous prime is 1031412213173. The next prime is 1031412213239. The reversal of 1031412213222 is 2223122141301.
It is a super-2 number, since 2×10314122132222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1031412213192 and 1031412213201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19173279 + ... + 19226997.
It is an arithmetic number, because the mean of its divisors is an integer number (64617102000).
Almost surely, 21031412213222 is an apocalyptic number.
1031412213222 is an abundant number, since it is smaller than the sum of its proper divisors (1036335050778).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1031412213222 is a wasteful number, since it uses less digits than its factorization.
1031412213222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61300.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1031412213222 its reverse (2223122141301), we get a palindrome (3254534354523).
The spelling of 1031412213222 in words is "one trillion, thirty-one billion, four hundred twelve million, two hundred thirteen thousand, two hundred twenty-two".
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